Blocking Diode
Blocking Diode
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US $79.99
Help with a diode circuit?
Search Vout for the circuit following when Vin = 12 V and when Vin =- 12V. http://imgur.com/MLLmd.jpg. To me, it seems In both cases, the circuit would act as a voltage divider with Vout = (equivalent resistance of resistors to ground) * Vin / Req but with negative stress, I think the node with the diode is open circuit so its only 100 ohms *- Vout = 12V / 100 ohms. The potential difference across the diode is to be taken at 0.6 V, but I can not see how that mattered. I see no current blocking diode across R2 if the voltage is negative. I am simplifying the problem?
Yes If not for Vin = -12 V is a simple voltage divider giving Vout = -6 V, however, for the positive case when the diode is in the way of progress, things get a bit more complicated. To solve the circuit in two phases: a) the circuit without the diode and the associated resistance R2. This would give a voltage of 6 V with a source of resistance 50 Ohms (R1 R2 in parallel) b) as a second step adds the resistance R2 is connected to a fixed 0.6 V point. The equivalent circuit has a resistance of 50 ohms connected to 6 V and 100 Ohm resistor connected to 0.6 V This voltage divider circuit is to have a current equivalent of 5.4 V / 150 mA = 36 ohms voltage across R2 is 36 mA * 100 ohms = 3.6 V Vout = 3.6 V + 0.6 V = 4.2 V